Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

triangles

Asked by 13th February 2009, 10:33 PM
Answered by Expert
Answer:

Draw triangle PQR,  with PQ=PR= 5 cm.9 for convenience sake take the base as RQ.)

Draw a ray  RT making an  acute angle QRS with the side QR( below QR)

With the pointed end of the compass on R mark 7 points at equal distances on RS.

Mark the 7th point  from R as T.

 join TQ.

Mark the 6th point   from R as S.

Thru' S ,  construct  a line segment  parallel to TQ.

Let this line segment meet the side RQ at A .

Thru' A construct a line segment AB parallel to  PQ meeting RP in A.

ABR will be the triangle similar to triangle  PQR.

 

Answered by Expert 14th February 2009, 5:48 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!