CBSE Class 10 Answered
triangles
Asked by suchet_r | 30 Aug, 2009, 08:17: PM
Expert Answer
Pythagoras' Theorem,
In ΔPQR
PR2 = PQ2 + QR2
QR = 2QS
PR2 = PQ2 + (2QS)2
PR2 = PQ2 + 4QS2 ..........(1)
In ΔPQS
PS2 = PQ2 + QS2
QS2 = PS2 - PQ2
Using this in (1),
PR2 = PQ2 + 4(PS2 - PQ2)
PR2 = 4PS2 - 3PQ2
Regards,
Team,
TopperLearning.
Answered by | 31 Aug, 2009, 12:20: AM
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