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CBSE - X - Mathematics - Three Dimensional Geometry

triangles

Asked by suchet_r 30th August 2009, 8:17 PM
Answered by Expert

Answer:

Pythagoras' Theorem,

In ΔPQR

PR2 = PQ2 + QR2

QR = 2QS

PR2 = PQ2 + (2QS)2

PR2 = PQ2 + 4QS2 ..........(1)

In ΔPQS

PS2 = PQ2 + QS2

QS2 = PS2 - PQ2

 Using this in (1),

PR2 = PQ2 + 4(PS2 - PQ2)   

PR2 = 4PS2 - 3PQ2

Regards,

Team,

TopperLearning. 

Answered by Expert 31st August 2009, 12:20 AM

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