CBSE Class 10 Answered
triangles
Asked by | 13 Feb, 2009, 10:25: PM
Expert Answer
A,B and C are the interior angles of a triangle.
So,
A + B+ C= 180
Now,
sin[( B+C)/2]=sin [(180-A)/2]
=sin[90-(A/2)]
=cos(A/2)
Answered by | 14 Feb, 2009, 05:33: PM
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