CBSE Class 12-science Answered
Three identical cars A, B and C are moving at the same speed on three bridges. The car A goes on a plane bridge, B on a bridge convex upward and C goes on a bridge concave upward. Let F1, F2 and F3 be the normal forces exerted by the cars A,B and C respectively on the bridges when they are at the middle of bridge.
a) F1 Is maximum of the three forces
b) F2 is maximum of the three forces
c F3 is maximum of the three forces
d) F1= F2 = F3
What is the answer of the above question? What is the meaning of “normal forces exerted by the cars on the bridges” mentioned in the question? Is it normal reaction or weight?
Please explain option ‘c’ and ‘d’ in detail.
Asked by shubham.padamwar.3 | 19 Dec, 2014, 03:06: PM
Expert Answer
Given that:
Case 1:
The first car A is going on a plane bridge as shown,
The normal force FA = mg
Case2:
Car B goes on a convex upward bridge:
Here the centripetal force mv2 /r = mg - FB
Case 3:
Car C goes on a concave bridge:
Centripetal force mv2 /r = Fc - mg
Hence we get that:
Therefore FC is the maximum of the three forces.
Answered by Jyothi Nair | 21 Dec, 2014, 05:04: PM
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