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THIS ONE IS SIMPLE BUT ITS NOT CLICKING MY MIND......ABCD IS A QUADRILATERAL IN WHICH DIAGNOL BD PERPENDICULAR TO THE SIDE AB,IF AB=4.5CM,AD=7.5 AND THE DISTANCE OF C FROM BD=1.5.FIND THE AREA OF THE QUADRILATERAL.(WITH DIAGRAM)
 

Asked by binodbharali 14th June 2016, 8:49 PM
Answered by Expert
Answer:
In space right space increment ABD comma
BD squared equals AD squared minus AB squared
rightwards double arrow BD squared equals left parenthesis 7.5 right parenthesis squared minus left parenthesis 4.5 right parenthesis squared
rightwards double arrow BD equals square root of 56.25 minus 20.25 end root equals square root of 36 equals 6 space cm
Area space of space quadrilateral space ABCD equals area space of space increment ABD space plus space area space of space increment BCD
area space of space increment ABD space equals 1 half cross times base space cross times height equals 1 half cross times AB space cross times BD equals 1 half cross times 4.5 space cross times 6 equals 13.5 space cm squared
area space of space increment BCD space equals 1 half cross times base space cross times height equals 1 half cross times BD space cross times CM equals 1 half cross times 6 space cross times 1.5 equals 4.5 space cm squared
therefore comma space area space of space quadrilateral space ABCD equals 13.5 space cm squared plus 4.5 space cm squared equals 18 space space cm squared space
Answered by Expert 15th June 2016, 10:12 AM
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