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Home / Doubts and Solutions/JEE/Chemistry

This is my question

Asked by rbhatt16 6th October 2017, 9:37 PM
Answered by Expert
Answer:
T h e space r e a c t i o n space i s space 2 N subscript 2 O subscript 5 space rightwards arrow space 4 N O subscript 2 space plus space O subscript 2 space R a t e space equals space space minus 1 half fraction numerator increment left square bracket N subscript 2 O subscript 5 right square bracket over denominator increment t end fraction equals plus 1 fourth fraction numerator increment left square bracket N O subscript 2 right square bracket over denominator increment t end fraction equals fraction numerator increment left square bracket O subscript 2 right square bracket over denominator increment t end fraction R a t e equals negative 1 half fraction numerator increment left square bracket N subscript 2 O subscript 5 right square bracket over denominator increment t end fraction equals negative 1 half open square brackets fraction numerator 2.08 minus 2.33 over denominator 184 end fraction close square brackets equals 6.79 space x 10 to the power of negative 4 end exponent m o l L to the power of negative 1 end exponent space m i n to the power of negative 1 end exponent I n space u n i t s space o f space h r s R a t e space equals space 6.79 space x space 10 to the power of negative 4 end exponent space x space 60 space equals space 4.076 space x space 10 to the power of negative 2 end exponent space m o l space L to the power of negative 1 space end exponent h r to the power of negative 1 end exponent I n space u n i t s space o f space s e c o n d s R a t e space equals space fraction numerator 6.79 x 10 to the power of negative 4 end exponent over denominator 60 end fraction equals 1.13 x 10 to the power of negative 5 end exponent space m o l space L to the power of negative 1 end exponent space s to the power of negative 1 end exponent T h e space r a t e space o f space p r o d u c t i o n space o f space N O subscript 2 space equals space 2 fraction numerator increment left square bracket N subscript 2 O subscript 5 right square bracket over denominator increment t end fraction equals 2 x open square brackets fraction numerator 2.08 minus 2.33 over denominator 184 end fraction close square brackets space equals space 2.72 space x space 10 to the power of negative 3 end exponent space m o l space L to the power of negative 1 end exponent space m i n to the power of negative 1 end exponent
Answered by Expert 8th October 2017, 7:41 PM
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