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CBSE Class 12-science Answered

There are two radionuclei A and B. A is an alpha emitter and B is a beta emitter. Their distintegration constants are in the ratio of 1 : 2. What should be the ratio of number of atoms of two at time t = 0 so that probabilities of getting alpha space a n d space beta particles are same at time t = 0.
(A) 2 : 1
(B) 1 : 2
(C) e
(D) e to the power of negative 1 end exponent
Asked by yugibo | 13 Apr, 2016, 09:35: PM
answered-by-expert Expert Answer
We know that half life is given as
begin mathsize 12px style straight T space equals space fraction numerator 0.693 over denominator straight lambda end fraction
Given space that space straight lambda space colon space straight lambda apostrophe space equals space 1 space colon space 2
therefore fraction numerator straight T space over denominator straight T apostrophe space end fraction equals space fraction numerator space straight lambda apostrophe over denominator space straight lambda end fraction equals 2 over 1
Thus comma space for space probabilities space of space getting space straight alpha space and space βparticles space at space the space same space time space straight t space equals space 0 comma space the space ratio space will space be space the space same space 2 space colon space 1. end style
Answered by Yashvanti Jain | 15 Apr, 2016, 04:41: PM
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