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CBSE Class 10 Answered

There are 104 students in class X and 96 students in class IX . In a house examination the students are to be evenly seated in parallel rows sick that no two adjacent rows are of same class. Find: a) the maximum No. Of parallel rows of each class for seating arrangement.  b) find the No. of students of class IX and X.
Asked by shubhastro2 | 04 Mar, 2018, 01:00: PM
answered-by-expert Expert Answer

The maximum no. of students to be seated in each row will be equal to the HCF of 96 and 104 which is 8.

now 96 students of 9th can be divided such that 8 per row = 12 rows

now only 96 out of 104 students of 10th can be included otherwise they won't be alternate

so 12 rows of 10th students 

also remaining 8 students can be made a row at the start

so it will look like

10th_9th_10th_9th_............9th_10th 

so total 25 rows 12+13

Answered by Arun | 04 Mar, 2018, 02:05: PM
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