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The work function of potassium is 2.0eV when it is illuminated by light of wavelength 3300angstrom photo electrons are emitted the stopping potential of photo electron is 

Asked by abduljaffer789 10th September 2018, 12:40 AM
Answered by Expert
Answer:
Einsteins Photo electric equation is " eV = h×(c/λ) - φ0 " ....................(1)
 
where eV is stopping potential in electron-volt, h is plancks constsant, c is speed of light, λ is wavelength and φ0 is work function.
 
substitututing the given data,  φ0 = 2 eV and λ = 3300 Aº with the required constants, we get
 
begin mathsize 12px style V space equals space fraction numerator h cross times c over denominator lambda cross times e end fraction space minus space phi subscript 0 over e space space equals fraction numerator 6.626 cross times 10 to the power of negative 34 end exponent cross times 3 cross times 10 to the power of 8 over denominator 3300 cross times 10 to the power of negative 10 end exponent cross times 1.602 cross times 10 to the power of negative 19 end exponent end fraction space minus space fraction numerator 2 cross times 1.602 cross times 10 to the power of negative 19 end exponent over denominator 1.602 cross times 10 to the power of negative 19 end exponent end fraction space end style = 1.76 V
Answered by Expert 10th September 2018, 12:55 PM
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