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CBSE Class 11-science Answered

The vapour density of a volatile chloride of a metal is 74.6.If the specific heat of the metal is 0.55,calculate the exact atomic weight of the metal and the formula of its chloride.
Asked by Vidushi412 | 12 Sep, 2018, 08:01: AM
answered-by-expert Expert Answer
Given:
 
Vapour density = 74.6
 
Specific heat = 0.55 cal/g
 
According to Dulong-Petit's law,
 
Approx. space atomic space weight space equals space fraction numerator 6.4 over denominator Specific space heat end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 6.4 over denominator 0.55 end fraction Approx. space atomic space weight equals space 11.63
Therefore the metal must be boron.
 
Molecular mass = 2× Vapour density
 
                       = 2 ×74.6
 
                       = 149.2 
 
So, 
 
149.2 - 11.63 = 137.4
 
137.4 is the weight of chlorine only.
 
So space no. space of space chlorine space atoms space equals fraction numerator 137.4 over denominator 35.5 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 3.8 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space almost equal to space 3
 
The formula of metal chloride is BCl3 
Answered by Varsha | 12 Sep, 2018, 11:53: AM

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