Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

The vapor pressure of water is 12300 Pa at 27 C. Calculate the vapor pressure of 0.5 M solution of a non dissociating/non associating solute in it.
Asked by lekhakarthikeyan | 28 Aug, 2018, 06:29: AM
answered-by-expert Expert Answer
Given:
 
Vapour pressure of H2O p01 =12300 kPa
 
                                   =12.3 Pa
 
Molality of solution =0.5 m
 
Vapour pressure of solution =p1
 
1 molal solution means 1 mole of solute in 1000 g of solvent
 
0.5 molal solution means 0.5 mole of solute in 1000 g of solvent
 
Moles space of space solvent space left parenthesis straight H subscript 2 straight O right parenthesis space equals 1000 over 18 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 55.56 Moles space of space solvent space left parenthesis straight H subscript 2 straight O right parenthesis space equals 55.56 Mole space fraction space of space solute space straight X subscript 2 space end subscript space equals space open parentheses fraction numerator straight o.5 over denominator 0.5 plus 55.56 end fraction close parentheses space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.00891 fraction numerator straight P to the power of blank subscript 1 minus straight P subscript 1 over denominator straight P to the power of blank subscript 1 end fraction space equals straight X subscript 2 space end subscript fraction numerator 12.3 minus straight P subscript 1 over denominator 12.3 end fraction space equals space 0.00891 straight P subscript 1 space equals space 12.3 minus straight o.1097 space space space space space equals space 12.19 space kPa
Vapour pressure of solution is 12.19 kPa
 
Answered by Varsha | 28 Aug, 2018, 02:18: PM

Concept Videos

Multiple Choice Questions Practice Test
Answered Unanswered My Questions My Answers
CBSE 12-science - Chemistry
The vapour pressure of pure liquids A and B are 450 and 700 mm Hg respectively, at 350 K. Find out the composition of the liquid mixture if total vapour pressure is 600 mm Hg. Also find the composition of the vapour phase.
Asked by hannamaryphilip | 17 Apr, 2024, 11:20: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
120 GM Naoh is dissolved in 3dm³ aqcus solution find out its molarity and normality
Asked by sameerteli003 | 08 Apr, 2024, 11:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Why are equimolar solutions of sodium chloride and glucose not isotonic?
Asked by rashmij34 | 27 Feb, 2024, 04:42: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
At the same temperature, CO2 gas is more soluble in water than O2. Which one of them will have a higher value of KH, and why?   
Asked by sagarmishra | 27 Feb, 2024, 04:01: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
The formula of degree of dissociation
Asked by kalandi.charan.407 | 08 Feb, 2024, 01:42: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
state of phenomenon of osmosis
Asked by premkhare2006 | 24 Jan, 2024, 09:50: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
5g of NaOH is dissolved in 500ml of water. find the molarity of the solution
question image
Asked by saritanohar22 | 13 Jan, 2024, 01:25: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
A 10% solution of urea ( molar mass 60) is found to be isotonic with a 5% solution of an unknown non-electrolyte substance.The molecular mass of unknown substance is (a) 40% (b) 50% (c) 45% (d) 30%
question image
Asked by kaushikmisty07 | 31 Dec, 2023, 11:42: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
उस विलयन कि मोलरता की गणना कीजिए जिससे 5 ग्राम NaoH 450 ML विलियन में घुला हुआ है
Asked by kamlesh.kumar.malee | 20 Dec, 2023, 06:59: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
The boiling point of benzene is 353.23k. When 1.80g of a non-volatile solute was dissolved in 90g of benzene , the boiling is raised to 345.11k. Calculate the molar mass of solute (kb=2.53kg mol-1)
Asked by varinder2149 | 10 Dec, 2023, 08:21: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt
Get Latest Study Material for Academic year 24-25 Click here
×