CBSE Class 11-science Answered
The value of KW is 9.55 x 10-14 at a certain temperature. Calculate the pH of water at this temperature ?
Asked by Deepak Singh | 24 Feb, 2015, 09:42: PM
Expert Answer
Solution:
Given
Kw = 9.55x10-14
For water [H+] = [OH-]
So Kw = [H+] x [H+] =[H+]2
[H+]2 = 9.55x10-14
[H+] = (9.55x10-14)1/2
p H = -log[H+] = -log[3.09x10-7] = -log3.09 – log10-7
= -[-7 + 0.4900] = 6.51
Answered by Vaibhav Chavan | 25 Feb, 2015, 11:11: AM
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