NEET Class neet Answered
the unit vector perpendicular to A=2i+3j+k and B=I+j+k is
Asked by suseelakada123 | 25 Jul, 2021, 03:22: PM
Expert Answer
Let 
and 
and unit vector perpendicular to 
and 
is detromined by taking cross product of and and
and is detromined by taking cross product of and andnormalizing the cross product by dividing its magnitude in order to make unit vector .
Hence unit vector 
perpendicular to and is , = (1/√6) ( 2 
- 
- 
)
perpendicular to and is , = (1/√6) ( 2 - - )-------------------------------------------
If 
, then 
, then Above vector relation is shown in fig.1. Since 
is sum of 
and 
, We can form a parallelogram with sides and .
is sum of and , We can form a parallelogram with sides and . is diagonal of parallelogram. Since all vectors have equal magnitude , this parallelogram becomes rhombusand is made of two equilateral triangle.
Hence each angle in the rhombus is 60o as shown in figure. Angle between and is 120o .
and is 120o .In similar manner, we get angle between and 
is 60o , if 
, or 
and is 60o , if , or Hence ratio between angles , θ1 : θ2 = 120 : 60 = 2 : 1
Answered by Thiyagarajan K | 25 Jul, 2021, 04:51: PM
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