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CBSE Class 9 Answered

the T.S.A  of a hollow cylinder open from both sides is 4620 cm2  and area of the base ring is 115.5 cm2.Find the thickness of the cylinder, if its height is 19 cm ?
Asked by nisha_vini29 | 08 Feb, 2016, 11:59: AM
answered-by-expert Expert Answer
Let space straight R space be space the space outer space radius space and space straight r space be space the space inner space radius space of space the space hollow space cylinder. Area space of space the space base space space ring space is space 115.5 space cm squared straight pi open parentheses straight R squared minus straight r squared close parentheses space equals 115.5 open parentheses straight R squared minus straight r squared close parentheses equals space 36.75 open parentheses straight R plus straight r close parentheses open parentheses straight R minus straight r close parentheses equals space 36.75............. left parenthesis 1 right parenthesis Total space surface space area space of space straight a space hollow space cylinder space equals space 4620 2 πRh plus 2 πrh plus 2 straight pi open parentheses straight R squared minus straight r squared close parentheses space equals space 4620 2 straight pi cross times 19 cross times open parentheses straight R plus straight r close parentheses plus 231 space equals 4620 2 straight pi cross times 19 cross times open parentheses straight R plus straight r close parentheses equals 4389 open parentheses straight R plus straight r close parentheses equals 36.75.......... left parenthesis 2 right parenthesis From space left parenthesis 1 right parenthesis space and space left parenthesis 2 right parenthesis space we space get space 36.75 cross times open parentheses straight R minus straight r close parentheses equals space 36.75 open parentheses straight R minus straight r close parentheses equals space 1 space cm So space thickness space of space cylinder space is space 1 space cm.
Answered by Vijaykumar Wani | 08 Feb, 2016, 12:31: PM

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