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ICSE Class 8 Answered

The total surface of a hollow cylinder which is open from both sides is 4620 sq cm, area of a base ring is 115.5 sq cm and height is 7 cm. Find the thickness of the cylinder.
Asked by iamsrjman | 20 Jul, 2019, 09:39: AM
answered-by-expert Expert Answer
U sin g space a r e space o f space b a s e comma space w e space g e t straight pi left parenthesis straight R squared minus straight r squared right parenthesis equals 115.5 rightwards double arrow left parenthesis straight R plus straight r right parenthesis left parenthesis straight R minus straight r right parenthesis equals 147 over 4.... left parenthesis 1 right parenthesis Total space surface space area space of space cylinder equals 4620 space cm squared rightwards double arrow Outer space curved space surface space area plus Innner space curved space surface space area plus 2 left parenthesis area space of space base right parenthesis equals 4620 space cm squared rightwards double arrow straight R plus straight r equals 399 over 4 rightwards double arrow straight R minus straight r equals 0.368 space cm Hence space the space thichness space is space 0.368 space cm.
Answered by Renu Varma | 20 Jul, 2019, 07:03: PM

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