CBSE Class 8 Answered
The total number of factors of the number N = 411 * 145 * 112 ?
Asked by Ramesh | 14 Nov, 2018, 11:15: PM
Expert Answer
To get the number of factors of a given number, we need to express the given number as a product of powers of prime numbers.
The sum of power indices are the number of factors of that given number.
Given number = 411 × 145 × 112 = 222 × (2×7)5 × 112 = 227 × 75 × 112
number of factors is 27+5+2 = 34
Answered by Thiyagarajan K | 17 Nov, 2018, 02:40: AM
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