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CBSE Class 12-science Answered

The total magnification produced  by a compound microscope is 20.The magnification produced by the eyepiece is 5.The microscope is focussed on a certain object.The distance between the objective and eyepiece is observed to be 14cm.If the least distance of distinct vision is 20cm calculate the focal length of the objective and the eyepiece.
Asked by vasturushi | 03 Feb, 2018, 08:19: PM
answered-by-expert Expert Answer
Overall magnification begin mathsize 12px style m space equals space m subscript o m subscript e space equals space open parentheses L over f subscript o close parentheses open parentheses D over f subscript e close parentheses end style = 20
begin mathsize 12px style D over f subscript e space equals space 5 semicolon space space h e n c e space open parentheses L over f subscript 0 close parentheses space equals space 4 semicolon b u t space D space equals space 20 semicolon space space h e n c e space f o c a l space l e n g t h space o f space e y e space p i e c e space f subscript e space equals space 4 space c m d i s tan c e space b e t w e e n space o b j e c t i v e space a n d space e y e space p i e c e space equals space f subscript 0 plus L plus f subscript e space equals space f subscript 0 plus 4 f subscript 0 plus f subscript e space equals space 14 space c m h e n c e space f o c a l space l e n g t h space o f space o b j e c t i v e comma space f subscript 0 space equals space 2 space c m end style
 
here it is assumed the image of objective lens is formed ner to focal point of eyepiece

Answered by Thiyagarajan K | 06 Feb, 2018, 12:53: PM

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