The time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is 0.4ms−10.4ms−1. The amplitude of oscillation is
Asked by nipunverma59
7th October 2018,
1:47 PM
Answered by Expert
Answer:
Equation of SHM :- x = A×sinωt .............(1)
where x is displacement, A is amplitide and ω is angular spped
if we differentiate eqn.(1), we get (dx/dt) = Aω×cosωt ....................(2)
angular speed ω = 2π/T = 2π/16 = 0.125π ......................(3)
by substituting ω from eqn.(3) and using eqn.(2) we get 
Answered by Expert
7th October 2018,
5:28 PM
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