The surface area of the upper area of the submarine is 200 m². If the submarine is 70m below the sea water, calculate the total force acting on its upper surface. [ Density of sea water= 1040 kg m^-3 , density of mercury = 13,600 kg m^-3 , atmospheric pressure= 75 cm of mercuy and g= 10ms^-2].

Asked by Topperlearning User 4th June 2014, 1:23 PM

Answered by Expert

Answer:

Surface area (A) of upper surface= 200 m²

Pressure due to air= x x g = 0.75m x 13600 kg m_^-3x 10 ms^-2 = 1,02,000 Pa.

Pressure due to sea water only= x x g = 70m x 1040 kg m^-3 x 10 ms^-2

= 7,28,000 Pa.

Therefore, total pressure (P) acting on the surface of submarine= ( 7,28,000 + 1,02,000) = 8,30,000Pa.

Total force acting on the submarine= P x A = 83000 x 200

= 166,000,000 N.

Answered by Expert 4th June 2014, 3:23 PM

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The surface area of the upper area of the submarine is 200 m². If the submarine is 70m below the sea water, calculate the total force acting on its upper surface. [ Density of sea water= 1040 kg m^-3 , density of mercury = 13,600 kg m^-3 , atmospheric pressure= 75 cm of mercuy and g= 10ms^-2].

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The surface area of the upper area of the submarine is 200 m2. If the submarine is 70m below the sea water, calculate the total force acting on its upper surface. [ Density of sea water= 1040 kg m-3 , density of mercury = 13,600 kg m-3 , atmospheric pressure= 75 cm of mercuy and g= 10ms-2].

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The surface area of the upper area of the submarine is 200 m². If the submarine is 70m below the sea water, calculate the total force acting on its upper surface. [ Density of sea water= 1040 kg m^-3 , density of mercury = 13,600 kg m^-3 , atmospheric pressure= 75 cm of mercuy and g= 10ms^-2].