Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

93219 24448 / 89292 63204

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

81783 72169
OR

Chat with us on WhatsApp

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Home / Doubts and Solutions/JEE/Chemistry

the resistance of a solution "A" IS 50 OHMS AND THAT OF SOLUTION 'B' IS 100 OHMS BOTH SOLUTIONS BEING TAKEN IN THE SAME CONDUCTIVE CELL
IF EQUAL VOLUMES OF SOLUTION  A   AND  B  ARE MIXED WHAT WILL BE THE THE RESISTANCE OF THE MIXTURE USING THE SAME CELL. 

Asked by sudheerkapoor67 9th October 2017, 6:08 PM
Answered by Expert
Answer:
Assume that K1 and K2 be the conductivity of the solution A and B respectively and the constant of the cell be 'x'.
Thus, for solution A, conductivity = Conductance x cell constant
begin mathsize 18px style K subscript 1 space equals space 1 over 50 cross times space x space space.... space left parenthesis 1 right parenthesis F o r space s o l u t i o n space B comma space c o n d u c t i v i t y space K subscript 2 space equals space 1 over 100 cross times space x space space space space.... left parenthesis 2 right parenthesis S i n c e space e q u a l space v o l u m e s space o f space A space a n d space B space a r e space m i x e d comma space b o t h space t h e space s o l u t i o n s space g e t space d o u b l y space d i l u t e d comma space h e n c e space t h e i r space i n d i v i d u a l space c o n t r i b u t i o n space t o w a r d s space t h e space c o n d u c t i v i t y space o f space t h e space m i x t u r e space w i l l space b e space left parenthesis K subscript 1 divided by 2 right parenthesis space a n d space left parenthesis K subscript 2 divided by 2 right parenthesis space r e s p e c t i v e l y space a n d space t h e space c o n d u c t i v i t y space o f space t h e space m i x t u r e space w i l l space b e space left parenthesis 1 divided by 2 right parenthesis left parenthesis K subscript 1 plus K subscript 2 right parenthesis H e n c e comma space f o r space t h e space m i x t u r e comma space space 1 divided by 2 left parenthesis K subscript 1 plus K subscript 2 right parenthesis space equals space left parenthesis 1 divided by R right parenthesis cross times space x space space....... left parenthesis 3 right parenthesis left parenthesis R space i s space t h e space r e s i s t e n c e space o f space t h e space m i x t u r e right parenthesis F r o m comma space e q u a t i o n s space 1 comma space 2 comma space a n d space 3 comma R space equals space 66.67 space o h m end style
Answered by Expert 10th October 2017, 12:35 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer 1/10

Report an issue
Previous Question
Next Question
Your answer has been posted successfully!

Free related questions

RELATED STUDY RESOURCES :
JEE QUESTION ANSWERS

Browse free questions and answers by Chapters

Trending Tags

trigonometric equations Mole concept linear equations circle trigonometric ratios integration functions matrix operations complex numbers arithmetic progression

Latest Questions

CBSE X Biology
What is enzyme  
Asked by Sureshgowdayd548 28th October 2020, 10:50 PM
JEE Main Mathematics
The following pseudocode is executed using the “Paragraph words” dataset. At the end of the execution, CountB captures the number of verbs with letter count less than the average letter count of verbs. But the pseudocode may have mistakes in one or more lines. Identify all such lines (if any). It is a Multiple Select Question (MSQ).  Error in Line 4  Error in Line 8  Error in Line 11  Error at Line 12  Error in Line 17  Error at Line 18  Error in Line 21 The following pseudocode is executed using the “Words” table. What will be the value of A at the end of the execution?
Asked by amaladelsingh 28th October 2020, 10:24 PM
CBSE X Biology
I want a brief clarity on Taxonomy
Asked by reenacharan2008 28th October 2020, 9:11 PM

Chat with us on WhatsApp