The reading of the ammeter in the adjoining figure will be :- |
Asked by Atulcaald
29th April 2018,
1:23 AM
Answered by Expert
Answer:
In the circuit given in the question, 6Ω, 3Ω and 2Ω are connected in parallel. Equivalent resistance of the parallel combination of these resistances is 1Ω.
Figure shows the circuit which replaces the above 3 parallel resistors with equivalent 1Ω resistance. Now total resistance in the circuit is 4Ω + 1Ω = 5Ω.
Then current in the circuit is 2V / 5Ω = 0.4 A
Answered by Expert
29th April 2018,
7:01 PM
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