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The radius of earth is 6400 km and g=10m/s square.in order that body of 5kg weighs zero at equator the angular speed of earth is

 

Asked by Sakshirangari27 17th July 2018, 11:34 AM
Answered by Expert
Answer:
There is a relationship for a body to be weightless at the equator.
 
 
That relationship is given by:
begin mathsize 12px style straight omega equals square root of straight g over straight R end root end style
where 'w' is the angular speed, 'g' is the acceleration due to gravity and R is the radius of the Earth.
 
 
Substituiting the given values in the above equation,
6400 km = 6400 x 103 m
 
begin mathsize 12px style straight omega equals square root of fraction numerator 10 over denominator 6400 cross times 10 cubed end fraction end root
straight omega equals square root of 1 over 640000 end root
straight omega equals 1 over 800 space rad divided by straight s end style
Answered by Expert 17th July 2018, 12:09 PM
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