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CBSE Class 11-science Answered

The question is attached above. Please send step by step complete solution. I also request you please do not send any web link to this question because I am unable to  open the link every time  .
Asked by sudhanshubhushanroy | 14 Dec, 2017, 06:54: AM
answered-by-expert Expert Answer
begin mathsize 16px style straight C subscript 0 minus straight C subscript 2 plus straight C subscript 4 minus straight C subscript 6 plus..... equals 2 to the power of straight n over 2 end exponent cos open parentheses nπ over 4 close parentheses.......... left parenthesis straight i right parenthesis straight C subscript 0 plus straight C subscript 2 plus straight C subscript 4 plus straight C subscript 6 plus..... equals 2 to the power of straight n minus 1 end exponent.............. left parenthesis ii right parenthesis Add space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis we space get straight C subscript 0 plus straight C subscript 4 plus straight C subscript 8 plus.... equals 1 half open parentheses 2 to the power of straight n minus 1 end exponent plus 2 to the power of straight n over 2 end exponent cos open parentheses nπ over 4 close parentheses close parentheses straight C subscript 0 plus straight C subscript 4 plus straight C subscript 8 plus...... equals fraction numerator 2 to the power of straight n minus 1 end exponent plus 2 to the power of straight n over 2 end exponent cos open parentheses nπ over 4 close parentheses over denominator 2 end fraction straight C subscript 0 plus straight C subscript 4 plus straight C subscript 8 plus...... equals 2 to the power of straight n minus 1 end exponent over 2 plus fraction numerator 2 to the power of straight n over 2 end exponent cos open parentheses nπ over 4 close parentheses over denominator 2 end fraction straight C subscript 0 plus straight C subscript 4 plus straight C subscript 8 plus...... equals 2 to the power of straight n minus 2 end exponent plus 2 to the power of straight n over 2 minus 1 end exponent cos open parentheses nπ over 2 close parentheses end style
Answered by Sneha shidid | 19 Dec, 2017, 10:25: AM

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