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Home / Doubts and Solutions/JEE/Physics

The pt from where a ball is projected is taken as the origin of the coordinate axis the x and y components of its displacement are given by x= 6t and y=8t-5t^2 what is the velocity of projection?

Asked by m.nilu 3rd July 2018, 6:41 PM
Answered by Expert
Answer:
begin mathsize 12px style X left parenthesis t right parenthesis space equals space 6 space t space semicolon space fraction numerator d X over denominator d t end fraction equals 6 Y left parenthesis t right parenthesis space equals space 8 space t space minus space 5 space t squared space semicolon space fraction numerator d Y over denominator d t end fraction space equals space 8 space minus space 10 space t space semicolon v e l o c i t y space V left parenthesis t right parenthesis space equals space V subscript X space i with rightwards arrow on top space plus space V subscript Y space j with rightwards arrow on top space equals space 6 space i with rightwards arrow on top space plus space open parentheses 8 space minus space 10 space t close parentheses j with rightwards arrow on top v e l o c i t y space a t space p r o j e c t i o n comma space a t space t space equals space 0 space comma space V left parenthesis 0 right parenthesis space equals space 6 space i with rightwards arrow on top space plus space 8 space j with rightwards arrow on top space equals space square root of 6 squared plus 8 squared end root space equals space 10 space m divided by s end style
Answered by Expert 4th July 2018, 12:32 PM
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