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The position of a particle is given by r vector= 3ti-2t^2j +4k m, where t is in seconds and the coefficients have proper units for r to be in metres. Find the velocity and acceleration of the particle at t= 2s. Pls explain

Asked by Sahar 27th January 2016, 6:15 PM
Answered by Expert
Answer:

begin mathsize 14px style Hi space Sahar comma straight r equals 3 straight t straight i with overparenthesis on top plus 2 straight t squared straight j with overparenthesis on top plus 4 straight k straight m with overparenthesis on top Now comma space velocity space will space be straight v equals dr over dt equals 3 straight i with overparenthesis on top plus 4 straight t straight j with overparenthesis on top therefore At space straight t equals 2 space straight s straight v equals 3 straight i with overparenthesis on top plus 8 straight j with overparenthesis on top space straight m divided by straight s  Similarly space the space acceleration space is straight a equals dv over dt equals 0 plus 4 straight j with overparenthesis on top Therefore comma space the space acceleration space is space independent space of space straight t space and space is space straight a space constant space 4 straight j with overparenthesis on top straight m divided by straight s squared end style

Answered by Expert 27th January 2016, 6:22 PM
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