CBSE Class 11-science Answered
The position of a particle is given by r = 4ti +2t^2j)m. Its Y component of velocity at t =1s is
Asked by arushidabhade | 21 Jul, 2019, 07:58: PM
Expert Answer
position vector, r = ( 4t i + 2t2 j ) m
velocity vector, dr/dt = ( 4 i + 4t j ) m
y- component, vy = 4t ; y-component at t =1 s , vy = 4×1 = 4 m/s
Answered by Thiyagarajan K | 21 Jul, 2019, 09:23: PM
CBSE 11-science - Physics
Asked by sheikhsaadat24 | 17 Apr, 2024, 09:41: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sy123946 | 07 Apr, 2024, 04:23: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by derhebha955 | 03 Apr, 2024, 09:03: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sumedhasingh238 | 29 Mar, 2024, 05:15: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by om636694 | 04 Mar, 2024, 09:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rajuinwati12 | 04 Mar, 2024, 09:22: AM
ANSWERED BY EXPERT