CBSE Class 9 Answered
The
polynomials kx3 + 3x2 - 8 and 3x3 - 5x + k
are divided by x + 2. If the remainder in each case is the same, find the
value of k.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Let p(x) = kx3 +3x2 -8 and q(x) = 3x3 -5x +k
When divided by (x+2), the remainders are p(-2) and q(-2).
p(-2) = k(-2)3+3(-2)2-8=-8k + 4
q(-2) = 3(-2)3-5(-2)+k= -14 + k
Given that, p(-2) = q(-2)
-8k + 4 = -14 + k
-9k = -18
k = 2
Answered by | 04 Jun, 2014, 03:23: PM
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