CBSE Class 11-science Answered
The pH of lemon juice is 2.32 at 298 k. What will be its [H3O+]?
Asked by Topperlearning User | 30 Apr, 2015, 08:49: AM
Expert Answer
pH = -log [H3O+]
2.32 = -log [H3O+]
antilog (- 2.32) = [H3O+]
[H3O+] = 4.786 x 10-3
[OH-] = 10-14 / 4.786 x 10-3 = 2.09 x 10-12
Answered by | 30 Apr, 2015, 10:49: AM
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