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The object is placed at a distance of 5/2f from convex lens of focal length f. Where exactly will the image form ? What is its position and the size and nature ?

Asked by Punnukam 16th March 2017, 4:10 PM
Answered by Expert
Answer:

Hi Punnu,

Using lens formula,

begin mathsize 12px style 1 over straight v equals 1 over straight f plus 1 over straight u equals 1 over straight f minus fraction numerator 2 straight f over denominator 5 end fraction equals fraction numerator 5 minus 2 straight f squared over denominator 5 straight f end fraction end style

Based on this value, it is not possible to ascertain the position, size, and nature.

Kindly check the question once. Is the object distance 5/2f correct? Or is it 2f/5?

Answered by Expert 16th March 2017, 5:53 PM
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