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The number of real roots of equation (x-1)^2 + (x-2)^2 + (x-3)^2) = 0 is?

A. 2       B. 1

C. 0       D. 3    

 

 

Asked by Mansi 7th July 2018, 11:22 AM
Answered by Expert
Answer:
begin mathsize 16px style open parentheses straight x minus 1 close parentheses squared plus open parentheses straight x minus 2 close parentheses squared plus open parentheses straight x minus 3 close parentheses squared equals 0
expand
3 straight x squared minus 12 straight x plus 14 equals 0
straight D space equals open parentheses negative 12 close parentheses squared minus 4 open parentheses 14 close parentheses open parentheses 3 close parentheses
equals 144 minus 168
equals negative 24
straight D less than 0
no space real space roots end style
Answered by Expert 10th July 2018, 11:19 AM
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