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The number of ions present in 2L of a solution of 1.6M K4FeCN6?

Asked by amitjena226 30th November 2017, 10:27 AM
Answered by Expert
Answer:
space space space space Molarity space space equals space fraction numerator no. space of space moles over denominator Volume space in space litre end fraction

therefore space No. space of space moles space of space straight K subscript 4 Fe left parenthesis CN right parenthesis subscript 6 space space equals space 1.6 cross times 2
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 3.2 space moles

1 space mole space of space straight K subscript 4 Fe left parenthesis CN right parenthesis subscript 6 space contain space 4 space straight K to the power of plus space ions space and space one space left square bracket Fe left parenthesis CN right parenthesis subscript 6 right square bracket to the power of minus space ion
So comma space total space number space of space ions space in space 3.2 space mole space equals space 3.2 cross times 5 cross times 6.023 cross times 10 to the power of 23 space space space space space
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 9.6 cross times 10 to the power of 24 space ions space
space space space space space space
Answered by Expert 30th November 2017, 1:19 PM
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