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The number of gram Atom present in 88.75g of chlorine  
Asked by vidhiparpani05 | 06 Jan, 2019, 01:02: PM
answered-by-expert Expert Answer
The number of gram atom present in 88.75g of chlorine is calculated as follows:
88.75 straight g space of space chlorine space equals space space fraction numerator 88.75 over denominator 35.5 end fraction space equals space 2.5 space moles As space we space know comma 1 space mole space chlorine space equals space 1 straight g space of space atom therefore 2.5 space moles space of space chlorine equals space 2.5 space straight g space atoms space of space chlorine
Answered by Ramandeep | 07 Jan, 2019, 04:10: PM

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ICSE 10 - Chemistry
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