Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

The no.of atoms of ozone present in 11.2 lit.of ozone at NTP are.........

Asked by 23rd February 2013, 8:29 PM
Answered by Expert
Answer:
Volume of 1 mole of gas at NTP is 24.0L.
Or we can say 22.4 lt of a gas at NTP has 6.022 x 1023 molecules.
 
So, 11.2 lt ozone will have = (6.022 x 1023  x 11.2 )/ 22.4  molecules of ozone.
Answered by Expert 24th February 2013, 12:00 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp