Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

The momentum of a body of mass 5kg is 10 kg m/s. A force of 2 N acts on the body in the direction of motion for 5 sec, the increase in kinetic energy is:

Asked by jadhaovishal636 6th December 2020, 8:37 AM
Answered by Expert
Answer:
Mass = m = 5 kg
 
Momentum = mv = 10 kg 
 
velocity v =  momentum / mass = 10/5 = 2 m/s
 
Applied force F = 2 N 
 
acceleration a = force / mass = 2 / 5 = 0.4 ms-2 
 
Change in speed after 5 seconds = v = vo + a t = 2 + ( 0.4 × 5 ) = 4 m/s
where vo is initial velocity
 
Change in kinetic energy = (1/2) m [ vf2 - vi2 ] = 0.5 × 5 × [ 42 - 2 2 ] = 30 J
where vf is final velocity and vi is initial velocity
Answered by Expert 6th December 2020, 11:11 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp