CBSE Class 9 Answered
The median BE and CF of ABC intersects at G. Prove that ar(GBC) = ar(quad AFGE)
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Join EF
EF will be parallel to BC.(mid point theorem)
ar (BEF) = ar(CEF) ( as area of triangles on same base and same two parallel lines are equal)
ar(BEF) - ar(GEF) = ar CEF - arGEF
arBFG = arCGE …(i)
Now ar (BEC) = ar(ABE) (BE is median)…(ii)
ar (BEC)- arCGE= ar(ABE)- arBFG equal areas subtracted from both sides in eq(ii)
Ar(BGC) = ar(quad AFGE)
Answered by | 04 Jun, 2014, 03:23: PM
Application Videos
Concept Videos
CBSE 9 - Maths
Asked by bascaljoseph | 07 Feb, 2023, 01:27: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by deepakumaraiya200 | 30 Jun, 2020, 09:51: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by kishor.kp14 | 15 Dec, 2019, 05:00: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by ravinderchoudhary0486 | 06 Dec, 2019, 10:59: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by kumarvsteel477 | 12 Sep, 2019, 08:22: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by phukansayan5 | 28 Aug, 2019, 06:16: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by arunpssac | 19 Aug, 2019, 07:02: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by yuvrajlkr8877 | 07 Aug, 2019, 09:31: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by rushabhjain.av | 01 Apr, 2019, 07:56: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by bhardwajvishesh2004 | 28 Nov, 2018, 04:18: PM
ANSWERED BY EXPERT