CBSE Class 11-science Answered
The mass of BaCO3 produced when excess CO2 is bubbled through a solution of 0.205 mol BA(OH)2 is
Asked by Anil | 12 May, 2017, 02:21: PM
Expert Answer
Moles of Ba(OH)2 =0.205
Hence 0.205 moles of Ba(OH)2 = 0.205 moles of BaCO3
So Mass of BaCO3 = moles of BaCO3 x molecular mass of BaCO3= 0.205 x 197.3=40.5g
Answered by Vaibhav Chavan | 12 May, 2017, 03:50: PM
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