NEET Class neet Answered
The magnitude of electric field E in the annular region of a charged cylindrical capacitor is .Please explain.
Ans is varies as 1/r, where r is the distance from the axis
Asked by valavanvino1011 | 12 Jun, 2019, 03:51: AM
Expert Answer
As shown in figure, electric field between the co-axial cylinder is due to charges on the inner cylinder.
A gaussian surface consists of imaginary cylinder of length and radius r is shown in figure.
By Gauss theorem we have, E×A = Q/ε .................(1)
here E is electric field, A is area of surface through which electric flux pass through,
Q is enclosed charge and ε is the permitivity of medium.
in eqn. (1) A = 2πr×L , hence E = 
....................(2)
....................(2)Hence if we assume Q' = Q/L = charge per unit length,
Electri field inside a cylindrical capacitor at a distance r from centre = Q' / ( ε 2π r )
Answered by Thiyagarajan K | 12 Jun, 2019, 08:27: AM
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