Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

9321924448

Mon to Sat - 10 AM to 7 PM

the magnetic field B at the centre of circular coil of radius r is π times that due to a long straight wire at a distance r from it, for equal currents. The adjoining diagram shown three cases in all cases the circular part has radius r and straight one are infinitely long. For the same current the field B at the centre P in cases 1,2,3 has the ratio

qsnImg
Asked by Prashant DIGHE 7th December 2019, 10:15 PM
Answered by Expert
Answer:
In the above configuration (1) , magnetic field at P has three contributions,
(i) due to semi infinite wire left of p, (ii) due to semi circle, (iii) due to semi-infinite wire at right side of p.
 
magnetic field due to left side semi-infinite wire and magnetic field due to right side semi-infinite wire cancel each other.
 
Hence net field due to semi circle = μo i / (4 r )
(Let us consider counterclockwise direction of current in loop gives +ve direction magnetic field )
 
------------------------------------------------------------
 
 
In the above configuration, magenetic field at P due to infinite wires is zero.
 
Semi-circle part of wire gives magnetic field -(μo i) / (4 r )
 
--------------------------------------------------------------------------------
In the above configuration, semi-finite wire at left side of P does not contribute magnetic field.
 
magnetic field at P due to three-quarter-circle gives magnetic field  -(3/4)(μo i) / (2r)
 
magnetic field at P due to semi-infinite wire at right side = (μo i) / (4πr)
 
Hence net magnetic field at P = - [ (3/4)(μo i) / (2r) ]+  [ (μo i) / (4πr) ]
 
-----------------------------------------------------
 
Hence ratio of magnetic field of three configuration = μo i / (4 r ) : -(μo i) / (4 r ) : - [ (3/4)(μo i) / (2r) ]+  [ (μo i) / (4πr) ]
 
Above ratio can be simplified to get ,  ( -π/2 ) : (π/2) : (3π/4) - (1/2)
Answered by Expert 8th December 2019, 11:28 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp