Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

the lines x+y=|a| and ax-y=1  intersect each other in the first quadrant .The set of all possible values of a is in the interval.
a.(1,-1)
b.(0,infinity)
c.(1,infinity)
d.(-1,infinity)

Asked by saraswatmajumder 27th October 2017, 10:29 PM
Answered by Expert
Answer:
begin mathsize 16px style straight x plus straight y equals open vertical bar straight a close vertical bar
ax minus straight y equals 1
Solving space these space equations space simultaneously space
you space get space straight x equals fraction numerator open vertical bar straight a close vertical bar plus 1 over denominator 1 plus straight a end fraction comma space straight y equals fraction numerator straight a open vertical bar straight a close vertical bar minus 1 over denominator 1 plus straight a end fraction
As space both space are space in space the space first space quadrant space both space are space greater space than space zero.
1 plus straight a greater than 0 space and space straight a open vertical bar straight a close vertical bar minus 1 greater than 0
After space solving space this space we space get space straight a greater than 1
straight a element of open parentheses 1 comma infinity close parentheses
end style
Answered by Expert 13th December 2017, 6:10 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!