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CBSE Class 9 Answered

The initial velocity of the projectile is equal to the velocity acquired by a freely falling body on reaching group when dropped height h. Then maximum horizontal range of that projectitle is
Asked by sarithamunnam | 20 Jul, 2018, 08:05: PM
answered-by-expert Expert Answer
Horizontal range R of projectile begin mathsize 12px style equals space fraction numerator u squared space sin 2 alpha over denominator g end fraction end style ....................(1)
where u is projection velocity and α is the angle of projection made with horizontal.
 
velcoity u acquired by a freely falling body from height h is given by,  begin mathsize 12px style u space equals space square root of 2 cross times g cross times h end root end style .....(2) 
Range is maximum when α = 45º
 
hence from(1) and (2), maximum range Rmax = 2×h
Answered by Thiyagarajan K | 23 Jul, 2018, 12:54: PM

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