CBSE Class 11-science Answered
The height and distance along horizontal plane of projectile are x=6t,y=8t-5t*t.What is the velocity when velocity is projected?
Asked by sagarikadevnath devnath | 01 Oct, 2013, 07:03: PM
Expert Answer
Given,
x = 6t and y = 8t-5t2
Comparing the equation,
x = 6t with x = (u cos?)*t
? u cos?= 6 (1)
And,
y = 8t-5t2 with y =(u sin? )*t (1/2) gt2
? u sin? = 8 ..(2)
Squaring (1) and (2) and adding,
u2cos2?+ u2sin2? = 62 + 82
u2(cos2?+ sin2?)= 36+64
u2 * 1 = 100 [since, cos2?+ sin2? = 1]
u2 = 100
u = 10 ms1 or 10 m/s
Answered by Faiza Lambe | 01 Oct, 2013, 09:44: PM
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