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The heat of combustion of benzene at constant volume was found to be 3263.9 kj/mol at 25 celcius calculate the heat of combustion of benzene in kj at constant pressure?

Asked by Arun Mathew 1st January 2013, 6:53 PM
Answered by Expert
Answer:
Given :   ?E = Heat of combustion at constant volume= 3263.9 kJ mol1
T = 298K
R = 8.314 Jk1 mol1
 
To Find :  ?H = Heat of combustion at constantpressure.
 
Formula :   ?H = ?E + ?nRT
 
The required thermo chemical equation for thecombustion of benzene is
 
C6H6 + 152 O2(g)  -------> 6CO2(g) +3H2O(l)
 
 
SO, ?n = no. of moles of gaseous products no. of moles of gaseous reactants= 6 (15/2)= 1.5
 
?H = 3263.9 + [( 1.5) 8.314 10 298]= 3263.9 3.71635= 3267.6 kJ mol1
Answered by Expert 2nd January 2013, 10:36 AM
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