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ICSE Class 6 Answered

The handle of a nutcracker is 18 cm long & a nut is placed 2 cm from its hinge. If a force of 36 kgf is placed on the nut, it will crack. Calculate the force which has to be applied at the end of the handle to crack the nut. 
Asked by banerjeeshipra.shipra | 07 Feb, 2019, 07:31: PM
answered-by-expert Expert Answer
Load = 36 kgf 
Load arm = 2 cm 
Effort = ?
Effort arm =18 cm 
 
Load x load arm = Effort x Effort arm 
36 kgf x 2 cm = Effort x 18 cm 
 
E f f o r t space equals space fraction numerator 36 space cross times space 2 over denominator 18 end fraction
Effort = 4 kgf 
 
Thus, to crack the nut the force of 4kgf must be applied at the end of the handle. 
Answered by Shiwani Sawant | 08 Feb, 2019, 12:28: PM
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