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ICSE Class 10 Answered

The handle of a nutcracker is 16 cm long and anut is placed 2 cm from its hinge,if a force of 4 kgf is applied at the end of the handle to crack it, what weight, if simply, placed on the nut will crack it ?
Asked by Vikas | 16 May, 2016, 12:22: AM
answered-by-expert Expert Answer

Hi,

Given that:

Distance of nut from fulcrum (d) = 2 cm

Distance of effort from fulcrum (D) = 16 cm

Load × Load arm = Effort × Effort arm

load × 2 cm = 4 kgf  × 16 cm

Load = 64 / 2 = 32 kgf

Answered by | 16 May, 2016, 06:23: PM

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