ICSE Class 6 Answered
The handle of a nut cracker is 18cm long and a nut is placed 2 cm from its hinge. If a force of 36 kgf placed on the nut it will crack. Calculate the force which has to be applied at the end of the handle to crack the nut.
Asked by loveme2kanha | 04 Oct, 2018, 07:59: PM
Expert Answer
load arm = 2 cm
load = 36 kgf
effort = ?
effort arm =18 cm
2 x 36 = Effort x 18
The force to be applied at the end of the handle to crack the nut is 4 kgf.
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