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ICSE Class 6 Answered

The handle of a nut cracker is 18cm long and a nut is placed 2 cm from its hinge. If a force of 36 kgf placed on the nut it will crack. Calculate the force which has to be applied at the end of the handle to crack the nut.
Asked by loveme2kanha | 04 Oct, 2018, 07:59: PM
answered-by-expert Expert Answer
load arm =  2 cm
 
load = 36 kgf
 
effort = ?
 
effort arm =18 cm
 
2 x 36 = Effort x 18
 
E f f o r t space equals space fraction numerator 2 space cross times space 36 over denominator 18 end fraction space equals space 4 space k g f
The force to be applied at the end of the handle to crack the nut is 4 kgf.
Answered by Shiwani Sawant | 05 Oct, 2018, 12:45: PM
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