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Home / Doubts and Solutions/JEE/Mathematics

 The greatest value of the fix) = 2 sin x + sin 2x on the interval function [0,3(3.14)]

 

Asked by sateesh06072002 26th August 2018, 6:14 AM
Answered by Expert
Answer:
begin mathsize 18px style straight f left parenthesis straight x right parenthesis equals 2 sin space straight x space plus space sin space 2 straight x straight f apostrophe left parenthesis straight x right parenthesis equals 2 cos space straight x space plus space 2 space cos space 2 straight x straight f apostrophe left parenthesis straight x right parenthesis equals 0 2 cos space straight x space plus space 2 space cos space 2 straight x equals 0 cos space straight x space plus space cos space 2 straight x equals 0 cos space straight x space plus space 2 space cos squared straight x minus 1 equals 0 open parentheses 2 cos space straight x space minus 1 close parentheses open parentheses cos space straight x space plus 1 close parentheses equals 0 cos space straight x equals space 1 half space space or space cos space straight x space space equals space minus 1 straight x equals nπ plus straight pi over 3 space space or space space straight x space equals nπ plus space straight pi....... open square brackets 0 comma 3 straight pi close square brackets straight x equals space straight pi over 3 comma space fraction numerator 4 straight pi over denominator 3 end fraction comma fraction numerator 7 straight pi over denominator 3 end fraction comma space straight pi comma 3 space straight pi sub space in space straight f left parenthesis straight x right parenthesis space space to space find space max space value. end style
Answered by Expert 27th August 2018, 1:32 PM
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