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The following reaction is a reversible reaction. The value of Kc for this reaction is 31.4 at 588K. CO(g) + H2O (g) rightwards harpoon over leftwards harpoon CO2 (g) + H2 (g) If a 10.00L vessel has 2.50 mol CO2 and H2O, and 5.00 mol CO2 and H2 gas at 588K, which way will the reaction proceed ?
Asked by Topperlearning User | 27 Apr, 2015, 04:15: PM
answered-by-expert Expert Answer
[CO] = .25 M
[H2O] = .25 M
[CO2] = .50 M
[H2] =.50 M
 
Hence, Qc = [CO2] [H2]/ [CO] [H2O] = 4
 

Since Qc < Kc, it will proceed in the forward direction.

Answered by | 27 Apr, 2015, 06:15: PM

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ANSWERED BY EXPERT ANSWERED BY EXPERT
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