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CBSE Class 12-science Answered

The first member of Balmer series of hydrogen spectrum has a wavelength 6563 A. compute the wavelength of second member.
Asked by rutujasarangmehta | 15 Mar, 2016, 06:56: PM
answered-by-expert Expert Answer
The wavelengths of different lines of the Balmer series are given by
begin mathsize 14px style 1 over straight lambda equals straight R subscript straight H open parentheses 1 over 2 squared minus 1 over straight n subscript straight i squared close parentheses comma space space space where space straight n subscript straight i equals 3 comma space 4 comma space 5 comma space... end style
For first member of Balmer series,
n2 = 3
begin mathsize 14px style 1 over straight lambda subscript straight alpha equals straight R subscript straight H open parentheses 1 fourth minus 1 over 9 close parentheses equals fraction numerator 5 straight R subscript straight H over denominator 36 end fraction straight lambda subscript straight alpha equals fraction numerator 36 over denominator 5 straight R subscript straight H end fraction equals 6563 straight A with degree on top end style
Syntax error from line 1 column 82 to line 1 column 123. Unexpected 'mathvariant'.
Answered by Faiza Lambe | 16 Mar, 2016, 09:59: AM

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