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the equation of line passing through the point 2 -3 and parallel to the line joining the points 1 2 and -1 5

Asked by kesavasanjeev 11th March 2019, 11:25 AM
Answered by Expert
Answer:
Line passing through (x1 , y1 ) and  (x2 , y2) is   :  begin mathsize 12px style y space minus space y subscript 1 space space equals space fraction numerator y subscript 1 space minus space y subscript 2 subscript blank end subscript over denominator x subscript 1 space minus space x subscript 2 end fraction open parentheses x space minus space x subscript 1 close parentheses end style
hence line passing through (1,2 ) and (-1,5)  : y-2 = [ (2-5)/(1+1) ] (x - 1)  or  (y-2) = (-3/2)(x-1)   or  3x + 2y = 7 ...............(1)
 
equation of the line parallel to eqn.(1)  is 3x+2y = k .....................(2)
 
where k is constant to be determined.
 
line given by eqn.(2) passes through (2, -3) ,  we substitute x and y value in eqn.(2) to get k
 
3(2) + 2(-3) = k   or k=0
 
Eqn. of required line is 3x+2y = 0
Answered by Expert 11th March 2019, 4:19 PM
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